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【Leetcode】【中等】【36. 有效的数独】【JavaScript】
来源:cnblogs  作者:孙达  时间:2019/10/8 9:10:02  对本文有异议

题目描述

36. 有效的数独

判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。

数字 1-9 在每一行只能出现一次。
数字 1-9 在每一列只能出现一次。
数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。

上图是一个部分填充的有效的数独。

数独部分空格内已填入了数字,空白格用 '.' 表示。

示例 1:

输入:

  1. [
  2. ["5","3",".",".","7",".",".",".","."],
  3. ["6",".",".","1","9","5",".",".","."],
  4. [".","9","8",".",".",".",".","6","."],
  5. ["8",".",".",".","6",".",".",".","3"],
  6. ["4",".",".","8",".","3",".",".","1"],
  7. ["7",".",".",".","2",".",".",".","6"],
  8. [".","6",".",".",".",".","2","8","."],
  9. [".",".",".","4","1","9",".",".","5"],
  10. [".",".",".",".","8",".",".","7","9"]
  11. ]


输出: true


示例 2:

输入:

  1. [
  2. ["8","3",".",".","7",".",".",".","."],
  3. ["6",".",".","1","9","5",".",".","."],
  4. [".","9","8",".",".",".",".","6","."],
  5. ["8",".",".",".","6",".",".",".","3"],
  6. ["4",".",".","8",".","3",".",".","1"],
  7. ["7",".",".",".","2",".",".",".","6"],
  8. [".","6",".",".",".",".","2","8","."],
  9. [".",".",".","4","1","9",".",".","5"],
  10. [".",".",".",".","8",".",".","7","9"]
  11. ]

输出: false
解释: 除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。
但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。


说明:

一个有效的数独(部分已被填充)不一定是可解的。
只需要根据以上规则,验证已经填入的数字是否有效即可。
给定数独序列只包含数字 1-9 和字符 '.' 。
给定数独永远是 9x9 形式的。

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/valid-sudoku
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

 

解答:

解答:

个人思路:

  1、检测每行是否有重复数字;

  2、检测每列是否有重复数字;

  3、检测每个3*3内是否有重复数字。

96ms

 

  1. /**
  2. * @param {character[][]} board
  3. * @return {boolean}
  4. */
  5. function isRepeat(arr) {
  6. let hash = {}
  7. for (let i = 0; i < arr.length; i++) {
  8. if (!isNaN(arr[i])) {
  9. if (hash[arr[i]]) {
  10. return false
  11. } else {
  12. hash[arr[i]] = 1
  13. }
  14. }
  15. }
  16. return true
  17. }
  18. var isValidSudoku = function (board) {
  19. let result
  20. let colArr = []
  21. let blockArr = []
  22. //每一行是否重复检测
  23. for (let i = 0; i < board.length; i++) {
  24. result = isRepeat(board[i])
  25. if (!result) {
  26. console.log('行重复')
  27. return false
  28. }
  29. }
  30. //每一列是否重复检测
  31. for (let i = 0; i < board.length; i++) {
  32. for (let j = 0; j < board[i].length; j++) {
  33. if (!colArr[j]) {
  34. colArr[j] = []
  35. }
  36. colArr[j].push(board[i][j])
  37. }
  38. }
  39. for (let i = 0; i < colArr.length; i++) {
  40. result = isRepeat(colArr[i])
  41. if (!result) {
  42. console.log('列重复')
  43. return false
  44. }
  45. }
  46. //3*3是否重复
  47. let block = 0
  48. for (let i = 0; i < board.length; i++) {
  49. let reset = block
  50. for (let j = 0; j < board[i].length; j++) {
  51. if (!blockArr[block]) {
  52. blockArr[block] = []
  53. }
  54. blockArr[block].push(board[i][j])
  55. if ((j + 1) % 3 === 0) {
  56. block++
  57. }
  58. if (j === 8) {
  59. block = reset
  60. }
  61. }
  62. if ((i + 1) % 3 === 0) {
  63. block += 3
  64. }
  65. }
  66. for (let i = 0; i < blockArr.length; i++) {
  67. result = isRepeat(blockArr[i])
  68. if (!result) {
  69. console.log('3*3重复')
  70. return false
  71. }
  72. }
  73. //以上三种检测都通过
  74. return true
  75. };
View Code

 

原文链接:http://www.cnblogs.com/2463901520-sunda/p/11620245.html

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